The lab report below was submitted as part of the coursework for CM1121 Basic Inorganic Chemistry. Please do not plagiarise from it as plagiarism might land you into trouble with your university. Do note that my report is well-circulated online and many of my juniors have received soft copies of it. Hence, please exercise prudence while referring to it and, if necessary, cite this webpage.
1.
Abstract
The experiment
involves the separation of two organic compounds which consist of an acidic and
neutral compound, their purification as well as their identification by use of their
melting points. Firstly, the separation is done by solvent extraction which
involves the addition of dichloromethane (CH2Cl2) and 2%
NaOH. The compounds dissolve in them, forming two layers of liquids which are
separated using a separating funnel. Secondly, the compounds are then recovered.
The neutral compound is obtained through simple distillation by distilling CH2Cl2
of lower boiling point off. The acidic compound is acidified by concentrated
HCl, forming a precipitate which can be recovered by vacuum filtration. Thirdly,
the acidic and neutral compounds are purified by single solvent and solvent
pair method respectively. The methods employed are determined by solubility
tests. Lastly, the compounds are identified by their melting points by use of
the melting point apparatus. The acidic compound identified is salicylic acid
and the neutral compound is dibenzalactone.
2.
Introduction
Solvent
extraction is one of the most important and common method used for separation
in laboratory and industrial scales. It has an extensive application in the
separation of radioactive materials such as the reprocessing of nuclear fuels1. In organic chemistry, solvent extractions
done in labs are usually small-scale, using a separatory funnel. In industrial
applications, batch-mode extraction is used on a much larger scale than
laboratory solvent extractions 2.
All
scientists like to observe systems, make observations and draw conclusions in
their results. it is like a protocol which if rigorously adhered to in e lab,
is most likely to turn a chance observation into an important discovery. In
organic chemistry, the fact that a sample has been taken from bottle on a shelf
is no assurance of purity or even that the substance is what the label says it
is. Labeling mistakes occur too frequently, especially in samples which have
been relabeled after purchase. Organic compounds also degrade on storage and
its stability under specific conditions of storage is impossible to estimate.
This self evident precaution is often overlooked y even the most experienced
research chemists, often to their downfall. The identification of an unknown
compound encapsulates the events which occur during any scientific
investigation, no matter how short or how grand.
In this
experiment, two organic compounds, one acidic compound and another neutral
compound are being separated. The possible neutral organic compounds are
hydrocarbons, alcohol, ketone or nitrile and acidic organic compounds are
carboxylic acids. The physical properties such as their densities and
solubilities and chemical properties such as acid-base reactions and reactivity
of both the acidic and neutral compounds must be taken into account to
determine their method of extraction.
The
carboxylic acid in the unknown compound is a long chain one (as seen from the
possible compounds in the lab manual). They are generally insoluble in water
and soluble in organic solvents. They can also react with a base to form a
carboxylate anion. RCO2H
+ NaOH RCO2 - Na+ (water soluble salt) + H2O
After reaction with an OH- ion, the solubility properties of the
carboxylic acid changes. The carboxylate anion is soluble in water but is
insoluble in organic solvents. Neutral compounds, on the other hand, are
insoluble in water but they are soluble in organic solvents. Solvent extraction,
or liquid-liquid extraction is used to capitalize on the each of their
different solubilities. The organic solvent chosen is dichloromethane and
aqueous solution of 2% NaOH. When CH2Cl2 is added to the
unknown compounds, both the carboxylic acid and the neutral compound would be
dissolved in it. When NaOH is added and shaken, the OH- ion reacts
with the carboxylic acid to form a carboxylate anion which is no longer soluble
in CH2Cl2 but soluble in water (in NaOH) due to the polar
bonds form with water, causing the carboxylic acid to move to the aqueous
layer. As the organic solvent and alkaline solution are immiscible, two layers
of liquids are formed based on differences in polarity and density. The
extractions of both the organic and aqueous layer are done multiple times as
extraction done for the first time may not lead to complete separations as
explained by the partition coefficient (in Discussion section). CH2Cl2
is extracted twice with the addition of NaOH to remove any acid and water
impurities from the organic layer. CH2Cl2 is then
extracted once more with addition of deionised water to remove any water
soluble impurities. The two NaOH and the deionised water layers are combined to
form the aqueous layer containing the carboxylate anion and the CH2Cl2
layer forms the organic layer containing the neutral compound.
The
carboxylic acid is precipitated with the use of concentrated HCl. The H+
ion in the acid would first react with the OH- ion in NaOH (H+ + OH-
à H2O).
After
all the OH- ions have been converted into water, the carboxylate
ion, RCOO- would react with the extra H+ to yield the carboxylic acid (RCOO-
+ H+ à RCOOH). Net equation is RCO2- Na+ + HCl àRCO2H (s) + NaCl.
Congo
Red paper is used to check if the solution contains excess H+. Congo
red paper turns blue when it detects free H+ ions. Since the long
chain carboxylic acid is insoluble in water, a precipitate is formed in the
solution. The solution is then filtered
to remove the aqueous solution of HCl from the carboxylic acid compound. Recrystallisation
of the carboxylic acid compound needs to be done to remove the impurities in
the compound.
The
organic layer is dried using a drying agent, anhydrous Na2SO4,
to remove any traces of water. This is done to achieve high purity of the
organic compound and to ensure smooth recrystallisation. Simple distillation is
carried out to distill off CH2Cl2, which has a boiling
point of 40 ̊C3, lower than that of
the neutral compound (whose melting point is above 60 ̊C which means its boiling point is above 60 ̊C as well). Two pieces of boiling chips placed in
the round bottom flask during the distillation process. They are small,
insoluble, porous stones made of calcium carbonate4 or silicon
carbide4. The pores in it trap air and provide spaces where bubbles
of solvent vapor can form. When a boiling chip is heated in a solvent, it
releases tiny bubbles, ensuring smooth and even boiling and prevent bumping and
boiling over and loss of the solution.
There are two types of recrystallisation
methods, namely, recrystallisation using a single solvent or using a solvent
pair. Solubility tests are conducted to ascertain the
method of recrystallisation that is to be used. The sample is added to either
water or ethanol. It is crucial to take note never to add too much sample as
saturated solution may not be able to dissolve the excess sample, causing ourselves
to mistaken the sample to be insoluble in the solvent.
After
recrystallisation is completed, the crystals are placed under the infra-red
lamp to remove any water content that may still be in the crystals. This step
is essential because the water content in the crystals has an impact on the
range of melting point of the compounds, causing an inaccurate deduction of the
identity of the compounds later on. After the removal of water in the crystals,
the melting points of the two compounds are determined using the melting point
apparatus.
3.
Experimental
The
apparatus that are needed are two dry 250mL conical flask, 4 test tubes and
test tube rack, retort stand, electronic balance, clamp for retort stand, metal
ring to support separatory funnel, separatory funnel, glass funnel, vacuum
flask, glass rod, beaker, infra-red lamp, distillation materials which include
dry round bottom flask, thermometer, thermometer holder, west condenser,
boiler, 2 vacuum tubes, water pump, 3 way connecting tube, 2 clamp holders and straight
tube adapter. The chemicals and materials needed are 80mL dichloromethane, 80mL
2% NaOH, 20mL of deionised water, one spoonful of anhydrous Na2SO4, boiling
chips, Congo Red paper, a few filter papers, ice, 5 mL concentrated HCl,
ethanol and cold deionised water.
Separation
by solvent extraction:
Place unknown sample and 70mL CH2Cl2 into 250mL conical
flask, swirling it to ensure all the solids have dissolved. Then transfer the
contents to the separatory funnel. Rinse the conical flask with 10mL of CH2Cl2
then pour it into the separatory funnel. Add 40mL of 2% NaOH into the
separatory funnel and shake it contents vigorously for 3 times, releasing the
stopcock each time. Allow it to stand for two layers to form. Drain the lower
organic layer into a conical flask and pour the aqueous layer into a beaker.
Place the organic layer back into the separatory funnel and repeat the steps
again with another 40mL of 2% NaOH and once more with 20mL of deionised water,
combining the drained NaOH and deionised water into one beaker and the organic
layer to a conical flask.
Recovery
of neutral compound:
Add a spoonful of anhydrous Na2SO4 into the organic layer
to remove any water impurities in it. Using a folded filter paper and a filter
funnel, filter the dried organic layer and place it into a dry round bottom
flask. Set up a simple distillation to remove CH2Cl2 as
distillate and stop the distillation process once no more distillate is
produced. Recover crude product N from the round bottom flask.
Recovery
of acidic compound by acidification:
Place the beaker containing the aqueous layer into an ice bath and add 5mL of
concentrated HCl. Check to see if the mixture is acidic by use of Congo paper
which should turn blue. Using the vacuum filtration method, collect precipitate
A.
Solubility
test: Using a
small amount of each of the two compounds and add each compound to a test tube
with 2mL of deionised water or ethanol. The solubility of the compounds in
deionised water and ethanol at room and hot temperatures are recorded. The test
results can be found on the Results section of this report. From the test
results, the acidic and neutral compound would have to undergo
recrystallisation by single solvent and solvent pair techniques respectively.
Recrystallisation
by single solvent:
Place the acidic compound A into a 100mL conical flask and a small amount of
100% deionised water is added. The solution is heated until all the solid have
dissolved. The solution is left to cool at room temperature and then in ice
water bath to allow crystallization. The crystals are filtered by vacuum
filtration and wash with cold solvent. Place the crystals under an infra-red
lamp to dry it further.
Recrystallisation
by solvent pair:
Place neutral compound N into a 100mL conical flask with 10mL ethanol and boil
it. Boiling deionised water is added drop-wise until a turbid solution is formed.
Then add ethanol drop-wise until the turbidity disappears. The mixture is
allowed to cool at room temperature then in ice water bath to allow
crystallization. The crystals are filtered by vacuum filtration and wash with
cold deionised water. Place the crystals under an infra-red lamp to dry it
further.
Identification
of compounds:
The mass of the plastic bag and two crystal compounds with the plastic bags are
then weighed separately and the readings are recorded. The results are shown in
the Results section in this report. Fit a minute portion of each of the
compounds into two capillary tubes. The first tube is used to measure the
approximate melting range with rapid heating of 20 ̊C gradient and the second tube to find a more
accurate melting range with slower heating of 1 ̊C
gradient. The range of the melting
points should be recorded between the temperature at which liquid is observed
and the temperature at which all the solid becomes a liquid. The melting point ranges
of the acidic and neutral compounds are recorded and their identities are
obtained when the melting points ranges are compared with those in the
laboratory manual.
4.
Results
Table
1: Solubility test results for compound A and N in water and in ethanol.
Solvent
|
Acidic
compound (A)
|
Neutral
compound (N)
|
||
Room
temp
|
Hot
|
Room
temp
|
Hot
|
|
Water
|
NS
|
S
|
NS
|
NS
|
EtOH
|
S
|
S
|
S
|
S
|
Solvent
used for recrystallization
|
Single solvent(water)
|
Solvent pair
|
NS: not soluble / poorly soluble S: soluble
From
this solubility tests, the solvent used for recrystallisation is single solvent
for compound A and solvent pair for compound N.
Table
2: Mass of crystals A and N obtained after purification.
Mass
(g)
|
Acidic
compound (A)
|
Neutral
compound (N)
|
Plastic
bag
|
0.65
|
0.65
|
Plastic
bag + purified product
|
2.07
|
0.94
|
Purified
product
|
1.42
|
0.29
|
Table
3: Melting point of crystals A and N
their identification.
Acidic
compound (A)
|
Neutral
compound (N)
|
|
Rough
melting-point range
(trial
run)/ 0C
|
157.3-159.0
|
107.5-113.5
|
Accurate
melting-point range (accurate run)/ 0C
|
158.4-158.9
|
110.1-110.4
|
Compound
identified
|
Salicylic acid
|
Dibenzalactone
|
The recrystallised
acidic compound identified is salicylic acid which has a melting point range of
158.4 ̊C -158.9 ̊C, which does not correspond to the experimental
value of 159.0 ̊C sharp5. Its
recrystallised appearance is white, which corresponds to its actual appearance
of white6 as well. The compound A is insoluble in water at room
temperature, as indicated in Table 1, corresponds to salicylic acid actual
property that it is poorly soluble in water at room temperature with a
solubility of 0.2g/100mL of H2O at 20 ̊C5.
The
recrystallised neutral compound identified is dibenzalactone which has a
melting point range of 110.1 ̊C -110.4 ̊C, which correspond to the experimental value of 110
̊C to 112 ̊C7. Its recrystallised appearance is dull
light brown, which does not correspond to its actual appearance of bright
yellow7 in colour. The compound N is insoluble in water at room
temperature, as indicated in Table 1, corresponds to dibenzalactone actual
property that it is insoluble in water but soluble in ethanol7.
Percentage Yields
of Compounds A and N
Percentage
Yield of Compound A
= × 100%
= ×100%
= 71.0 %
Percentage
Yield of Compound N
= × 100%
=×100%
= 14.5%
Percentage
Yield of Sample recovered
= × 100%
= 43.0%
5.
Discussion
Percentage yield
for compound A and N
The
yield from compound A can be considered good8 as it has a percentage
yield of approximately 71%. The yield is good because care was taken during
vacuum filtration by ensuring that the Buchner funnel fully covers the rubber
adaptor so that there is no leakage of the aqueous layer into the filter flask.
I have also made sure that the filter paper is wet as this would cause the
paper to adhere to the plate and keeps materials from passing under the paper
during filtration. Care was also taken to make sure that the
filter paper is secure on the filter, that air is being drawn through the
paper, and that all of your apparatus is securely clamped. The mixture of
concentrated HCl and the aqueous is then added slowly to the Buchner funnel,
ensuring that the pressure of the fluid passing through is not focused on one
point, but evenly spread out on the entire filter paper. This is to ensure that
the filter paper does not break and the particles from the aqueous layer do not
flow through the holes. Extra care was also taken to ensure that the particles
also do not creep under the edges of the filter paper.
However,
the yield could have been higher as there might be minute
amounts of the crystals could be lost during the processes of transferring them
from one container to another, when weighing them, or even blown away by the
wind. This
error is rather inevitable to a large extent, even though we may be extremely
careful. We can try
to make as little mass of the crystals lost as possible, and avoiding being
near fans which can blow the crystals away if we are not careful.
The
yield from compound N is considered poor8 as it has a percentage yield of 14.5%. The
brownish colour of compound N also has a stark difference from its actual
colour of bright yellow. This could be because I added a drop of concentrated
HCl into the solvent during recrystallisation by solvent pair by mistake. This
caused the ethanol to turn to a dark brown solution while heating on the hot
plate, instead of a white turbid. The dark brown solution is also unable to
turn turbid with addition of boiling water. With the help of a lab assistant,
simple distillation was done and the rotary evaporator was used to obtain the solid
for melting point analysis. The addition of a drop of concentrated HCl might
have introduced a substantial amount of impurities that causes the differences
in the colour and yield of the compound. Due to the large differences in the
colour and the possibility that impurities are introduced, the compound might
not even be dibenzalactone. This means that the drop of concentrated HCl might
have also changed the chemical structure of the true neutral compound, even
though it does not have any basic properties that could possibly react with an
acid. This could mean that the compound N identified is not dibenzalactone,
even though their melting points correspond. The experiment could be repeated
to obtain a more accurate deduction.
The process of drying
of both compounds also posed another problem, which is the loss of product. As
the product was left in the open,
under infra-red lamp, the
wind might blow away some of the smaller crystals thus affecting the
resulting yield of the product.
One method of improvement is to use a Petri dish instead of a watch
glass for the drying process. As the Petri dish comes with a cover, the product
is more protected. Another method would be to dry the crystals using a vacuum
oven, not only would this method effectively remove water from the crystals, it
is also relatively a faster method of drying crystals.
Other
reasons for the loss of compounds could be due to spillage during the
separating steps causing the loss of compounds or that they were lost during
transfer from one container to another because some were stuck on the walls of
the containers as the complete transfer of mixture was not possible. There were
also crystals were lost as they were stuck onto the filter paper after suction
filtration, and not all were collected. Also, some of the compound did not
crystallize out during cooling, meaning to say that crystallization was
incomplete and some of the compound was still dissolved in the solution.
There
are also inaccuracies in the readings taken for the mass of the compounds and
this could be due to having water trapped between the crystals due to
insufficient drying, leading to bigger mass obtained and higher expected mass
of the compounds recovered, assuming other factors remaining a constant. Also,
during the initial stages of separation, there may not be a complete separation
even though extraction was done several times. This is because organic
compounds have certain affinity for organic solvents like dichloromethane.
Purity of the compounds
The products obtained are
generally considered quite pure, as the melting ranges obtained are near to
their literature values. Also, the melting range is narrow (approximately 2°C)9,
the products can be considered quite pure based on this small range. However,
there are still limitations to the melting ranges readings obtained. A very
small portion of the crystals was used to determine melting point, hence, the
results may not accurately reflect the purity of the actual product.
The recrystallised acidic
compound identified is salicylic acid which has a melting point range of 158.4 ̊C -158.9 ̊C,
which does not correspond to the experimental value of 159.0 ̊C sharp5. The melting point range is
lower than expected because there could be impurities present in the sample.
Impurities that are present in the sample may lead to lower than expected
melting point range.
There could also be errors that
may affect purity of compounds collected at the end, and affecting the melting
points eventually. When the melting range of the crystals is determined, the
change of the state of crystals between the first appearance of drops of liquid
within the sample to the disappearance of the last trace of solid of melting is
not very obvious, and therefore, making it difficult to judge the accurate
range. However, repeated readings were taken to narrow down the melting range
and obtain more accurate readings. Additionally, dust particles from the
surrounding may inevitably land in the mixtures to lower the purity of the
crystals when they are brought to test for their melting points.
However, if a broad melting point
range is obtained, this indicates a strong evidence for a lack of purity which
could mean that the pure substance decomposes on heating, introducing
impurities into it. The darkening of the sample or the evolution of gas is an
indication that this is occurring. Dissolution of the compound in residual or
occluded recrystallisation solvent will also give rise to a broad melting point
range9.
To
verify our results that the melting point range of our sample is similar to
that of the pure compound, we can make an intimate mix of the unknown sample
with a pure sample of the proposed material in equal proportions and obtain the
melting point of the mixture. If the substances are identical, then the melting
point with not change. However, if the melting point is different, this means
that the proposed compound is incorrect or that impurities are added that
lowers and broadens the melting point range. This technique is useful when
several possible candidate compounds within one or two degree Celsius of the
observed value which is evident for dibenzalactone and acetanilide melting
point range of 110 ̊C -112 ̊C and 113 ̊C
to 115 ̊C respectively whose values are
quoted from the lab manual.
Discussion of Methods Used
Extraction
using the differences in density of the two layers
One
advantage of this method is that two layers are formed which can be separated
easily. Acidic compound A reacted with aqueous NaOH to form a sodium salt. It
does not dissolve in the organic CH2Cl2 solvent as it is
inorganic, and hence it remained in the aqueous layer. For compound N, it will
dissolve in organic CH2Cl2 solvent and remained in the
organic layer. Since organic layer with compound N has a higher density, it
would be the lower layer. The upper aqueous layer, being less dense, would
consist of the compound A.
Another
advantage of this method is that it does not involve the setup of bulky
apparatus, giving the experiment accessibility. However, the handling part of
the separatory funnel can be quite difficult. It was important to release the
built up pressure inside the funnel after each gentle shake to mix the contents
inside with the stopper being held tightly. If not, the stopper, together with
the content would be expelled out of the funnel due to the immense pressure
built up. Besides, when the lower layer was drained out, the solvent should be
drained out as much as possible, so that the upper layer would not contain the organic
layer which will in turn affect the purity of the compound at the later part of
the experiment and affecting the melting point of the compounds eventually.
Furthermore, although two solvents are separated in two layers in the
separatory funnel, they may have the same color. And thus, no clear distinction
can be shown between the two layers of solvents.
Separatory funnel was shaked a few times
Shaking
the separatory funnel is also important to increase the contact area between
the two liquid phases. The solute will move to the layer in which it is most
soluble in. Compound N will move to the organic layer whereas sodium salt of
compound A will move to the aqueous layer.
Choosing
of an organic solvent
Firstly,
the organic solvent chosen must have a boiling point lower than the melting
point of the substance that is to be recrystallised later. If the boiling point of the solvent is too
high, the substance may come out of the solution as a liquid rather than as a
crystalline solid, causing the solid to oil out10. For this
experiment, an organic solvent of low boiling point must be chosen. Dichloromethane
has a low boiling point of 400C, enabling the solvent to be
distilled off easily during the isolation process of the compound from the
solvent. Secondly, the organic compound that is extracted using the organic
solvent must be more soluble in the organic solvent as compared to water. As
such, the organic compound must have high solubility in the organic solvent.
Most importantly, the organic solvent used must not be miscible with water so
as to form two different layers during extraction, enabling the separation of
the two compounds.
The
use of dilute 2% NaOH
Most
organic compounds are more soluble in organic solvents as compared to water.
Initially, compound A may be more soluble in the organic solvent as compared to
water. Dilute NaOH must be added to react with Compound A in order to form a
sodium salt. Salts are ionic and most of them (especially sodium salts) are
soluble in the aqueous layer and not in water-immiscible organic solvent. Therefore,
the addition of dilute NaOH is needed to ensure that compound A is more soluble
in the aqueous layer. Thus, separating compound A and N through liquid-liquid
extraction is possible.
Extraction
is done thrice (more than once)
In the
presence of 2 solvents, compounds A and N would have their own distribution or
partition coefficient with the following formula: Partition coefficient= solubility
of compound in dichloromethane/ solubility of compound in 2% NaOH. The
partition coefficient tells us the fraction of solute which is present in the
two solvents after extraction. If the partition coefficient for compound A is
1/7, 87.5% of A would be in the aqueous layer whereas the other 12.5% would
still be in the organic layer. As such, when we do extraction once, the yield
of compound A would only by 87.5%.
By
extracting compound A the second time by adding more NaOH, 87.5% of the
remaining 12.5% of A in the organic layer would be extracted into the aqueous
layer. This means that another 10.9% of A would be in the aqueous layer. A
third extraction would take 87.5% of the remaining 1.6% of A present in the organic
layer. The organic solvent would have 0.2% of compound A, which is a very small
amount. All in all, more than 99.8% A would be extracted into the aqueous
layer. Therefore, with increased number of extractions, the yield of the
extracted solute is actually greater.
Suction Filtration
It is an effective method in
separating liquids from solids as compared to the simple filtration with the
use of filter funnel. This is because suction filtration filters the crystals
faster as it sucks out the solvent into the filter flask by removing its
internal pressure. It also allows crystals to be washed easily. Less time would
also be spent drying the crystals under the Infra-Red Lamp as compared to
simple filtration as more solvent is being separated from the crystals in
suction filtration.
However, there are disadvantages
to this method. Firstly, it needs the vacuum machine to do the operation, this
means that suction filtration cannot be done if no such apparatus are
available. Also, a thicker filter paper would be needed to withstand the
pressure from suction filtration. If the filter paper was torn during suction
filtration due to the paper being not thick enough, there would be a loss of
crystals (residue), and suction filtration would have to be repeated to obtain
the maximum yield of crystals.
Excess
concentrated HCl is added to the aqueous mixture
During
extraction, compound A reacts with NaOH to form a water-soluble salt. Compound
A is converted to its original form as a carboxylic acid by an excess of
concentrated HCl. It must be added carefully until the mixture becomes acidic. After
acidification, compound A no longer dissolve in the aqueous solvent as it is no
longer ionic and thus, it is precipitated out of the solution. Suction
filtration is used to obtain compound A. Acidification must be done carefully, pouring
a small amount of acid and swirling each time because the acid-base
neutralization is exothermic. The change in temperature may affect the solubility
of compound A in the aqueous solvent which may affect the yield of the compound
obtained.
Anhydrous
Na2SO4 is added to the organic mixture
Anhydrous
Na2SO4 is a drying agent which would absorb all the water
present in the organic mixture. The lab manual mentioned to add a spoonful of
it into the solution of interest, to remove water from it. However, the more
correct procedure of drying the organic layer should be first adding a spoonful
of anhydrous Na2SO4. If all the drying agent clumps, add another
spoonful. To determine if it has clumped, stir the mixture with a clean and dry
spatula or swirl the mixture rapidly. If any portion of the drying agent flows
freely on the bottom of the container when stirred or swirled, enough drying
agent is used. Otherwise, it is necessary to continue adding the drying agent
until the clumping stops10. However, adding too much drying agent
may cause all the liquid to be absorbed. If this occurs, additional solvent
will have to be added to recover the product from the drying agent.
Use
of boiling chips
The
stones have tiny nucleating points on the chip where vaporization can take
place. The chip will relieve minor hot spots and prevent loss of product
through bumping. The introduction of a boiling chip into a hot liquid may
result in instant vaporization and loss of product.
Recrystallisation
Compound
A is not soluble in room temperature water but is soluble in hot water. As
such, a single solvent is used for recrystallisation of compound A. For
purification to occur, the impurities present must either be soluble in cold
water or insoluble in hot water. If the impurities are soluble in cold water,
the dissolved impurities would be removed in the final filtration of the cooled
solution to collect the crystals of the pure compound. If the impurities are
not soluble in hot water, insoluble impurities are removed by filtering the hot
mixture. Compound A is then cooled and crystallized and pure compound A can be
obtained.
Compound
N is not soluble in both cold and hot water but is soluble in both cold and hot
ethanol. Thus, a solvent pair of both water and ethanol must be used as a
mixture of ethanol and water provides a medium in which compound N is very
soluble in the hot medium but shows low solubility in the cold. This is useful
because at high temperatures, the ethanol-water mixture behaves like alcohol
and at low temperatures, it behaves like water. If the material is soluble in
ethanol, not many crystals come back from the alcohol alone. If the material is
insoluble in water, it is not possible to dissolve it. If a mixed solvent is
used, the properties of both solvents can be incorporated. Compound N is first
dissolved in a hot boiling ethanol. Water, in which compound N is insoluble to,
is slowly added drop wise to the boiling solution until it becomes turbid, the
turbidity is tiny crystals of compound coming out of the solution. Then,
ethanol is added drop wise until solution until the solution turns completely
clear. This is done to force the crystals back into the solution. The solution
is cooled for recrystallisation to occur. Pure compound N can be obtained. The
disadvantage of using this method is that sometimes the recrystallised compound
does not form crystals but oil instead. Compounds usually oil out if the boiling
point of recrystallisation solvent is higher than the melting point of the
compound. If the oil solidifies, the impurities are trapped in the solid ‘oil’
and the solid has to be purified again.
Washing
the crystals with cold deionised water
Deionised
water is used to remove the high polar molecules that could be on the crystals.
Deionised water is capable of attracting inorganic salts, strong acids, strong
bases, low-molecular weight organic compounds with less than 5 carbons such as
alcohols and amines10.
Cold
deionised water is used as the solubility of the compound is lower at cold
temperature (0oC) than at warm temperature (25oC), this
implies that less amount of the sample will be dissolved at the former
temperature when washed, leading to more crystals being crystallised.
Use
of Congo red paper
It is
used to check for acidity, to ensure that there is excess H+ available to
protonate the carboxylate ion after reacting with all the OH- ions. Other forms
of tests such as the use of pH indicator paper, pH meter or litmus paper can be
used.
Questions in manual
1.
[I.4]
Why rinse the conical flask with 10ml of dichloromethane? How many mL of
organic solution is there?
Some
of the solid sample might be still undissolved in the 70mL of dichloromethane
that was added and some of the sample might be still on the sides of the
conical flask instead of dissolving. Therefore, an extra of 10mL of
dichloromethane was added to dissolve the remaining undissolved solid sample.
The total amount of organic solvent is 80mL.
2.
[I.6]Why
the organic layer is the lower layer?
The
two layers that are formed are dichloromethane solution and 2% NaOH. The
organic layer of dichloromethane solution has a higher density than 2% NaOH,
which contains mostly water.
3.
[I.9]
How many mL of organic layer is there in the conical flask? How many mL of
aqueous layer is there in the beaker?
There
are 80mL of organic layer in the conical flask and 100mL of aqueous layer in
the beaker.
4.
[II.2]
Why should the organic layer be dry?
The
procedure of separating the organic compound from the two layers may have
caused it to be contaminated with traces of water. Drying is done to further
separate the aqueous layer from the organic layer and to remove the water
contamination. This is done to achieve high purity of the organic compound and
to ensure smooth recrystallisation.
5.
[IV.2]
Why for successful recrystallisation, the compound must be soluble in hot
solvent, but relatively insoluble in cold solvent.
The
compound has to be soluble in a hot solvent so that it can dissolve in it. The
compound has to be relatively insoluble in cold solvent so that it can
crystallize into its pure form from the solution.
6.
Can
ethanol be used as the organic solvent for the extraction in this experiment?
Ethanol cannot be used as the
organic solvent for the extraction in this experiment. For ethanol to be used
as an organic solvent, it must not be miscible with water so that two layers of
mixture would be able to form and the compounds can be separated. However,
ethanol is miscible in water as it is able to form hydrogen bonds with water
and hence, it would be able to dissolve in water. This would be a problem as
there would not be a clear separation between the organic layer and the aqueous
layer as both layers would mix together. As such, by using ethanol as an
organic solvent, it is impossible to separate compound A and N. Furthermore,
ethanol can react with the organic acid (Compound A) to form esters through esterification.
This may lower the yield of compound A and the esters form may even serve as
impurities. Thus, the compound A that would be obtained may not be as pure if
ethanol was used.
7.
Outline
in a flowchart how you would separate
p-bromobenzoic acid and p-cresol (m.p. 252-254 ºC, m.p. 32-34 Cº)
6. Conclusion
The sample was extracted, separated, recrystallised,
both the acidic and neutral compounds were determined by melting points and
respective percentage yields were calculated and are summarised below.
Neutral compound
|
Acidic compound
|
|
Mass obtained (g)
|
0.29
|
1.42
|
Melting point (oC)
|
110.1-110.4
|
158.4-158.9
|
Literature M.P. (oC)
|
110.0-112.0
|
159.0
|
Possible Compound
|
Salicylic
acid
|
Dibenzalactone
|
Percentage Yield (%)
|
14.5
|
71.0
|
7.
References
1.
The
Complex Formation- Association models of solvent extraction of ions, Journal of
Radioanalytical Chemistry, Vol 31(1976) S. Siekierski.
2.
Illustrated
Guide to Home Chemistry Experiments, Robert Bruce Thompson(April 1, 2008)
3.
http://cartwright.chem.ox.ac.uk/hsci/chemicals/dichloromethane.html
8.
Vogel,
A.I., Tatchell, A.R., Furnis, B.S., Hannaford, A.J. and P.W.G. Smith. Vogel's
Textbook of Practical Organic Chemistry, 5th Edition. Prentice Hall, 1996.
9.
Experimental
organic chemistry by L.M Harwood, C.J Moody and J.M Percy
10. Organic Laboratory Techniques, a
small scale approach by Donald L.Pavia, Gary M lampman, George S.Kriz and
Randall G.Engel
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